Question:
Find the equation of a circle with Centre $(a, a)$ and radius $\sqrt{2}$
Solution:
The general form of the equation of a circle is:
$(x-h)^{2}+(y-k)^{2}=r^{2}$
Where, $(\mathrm{h}, \mathrm{k})$ is the centre of the circle.
$r$ is the radius of the circle.
Substituting the centre and radius of the circle in he general form:
$\Rightarrow(x-a)^{2}+(y-a)^{2}=(\sqrt{2})^{2}$
$\Rightarrow(x-a)^{2}+(y-a)^{2}=2$
Ans; equation of a circle with Centre $(a, a)$ and radius $\sqrt{2}$
is:
$(x-a)^{2}+(y-a)^{2}=2$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.