Find the equation of a line

Question:

Find the equation of a line

whose slope is 4 and which passes through the point (5, - 7)

 

Solution:

As slope is given $m=4$ and passing through $(5,-7)$.using slope $-$ intercept 

form of equation of line, we will find value of intercept first

$y=m x+c$ ..........(1)

$-7=4(5)+c$

$-7=20+c$

$c=-7-20$

$c=-27$

Putting the value of c in equation (1), we have

$y=4 x+(-27)$

$y=4 x-27$

$4 x-y-27=0$

So, the required equation of line is $4 x-y-27=0$.

 

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