Find the equation of a line


Find the equation of a line

whose slope is - 3 and which passes through the point ( - 2, 3);



As slope is given $m=-3$ and line is passing through point $(-2,3) .$ Using

slope - intercept form of equation of line, we will find intercept first

$y=m x+c$ ................(1)





Putting the value of c in equation (1), we have

$y=-3 x+(-3)$

$y=-3 x-3$

$3 x+y+3=0$

So, the required equation of line is 3x + y + 3 = 0.


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