Find the equation of a line which cuts off intercept 5 on the x - axis and

As intercept is given i.e. c = 5 and angle given so first we will find slope of line.

$m=\tan \theta$

$m=\tan 60^{\circ} \Rightarrow \sqrt{3}$

Now using slope intercept form of the equation of a line

$y=m x+c$

$y=(\sqrt{3}) x+5$

$(\sqrt{3}) x-y+5=0$

So, the required equation of line is $(\sqrt{3}) x-y+5=0$