Find the equation of a line which is equidistant from the lines

For the equation of line equidistant from both lines, we will find point through which line passes and is equidistant from both line.

As any point lying on $x=-2$ line is $(-2,0)$ and on $x=6$ is $(6,0)$, so mid - point is

$(\mathrm{x}, \mathrm{y})=\left(\frac{-2+6}{2}, \frac{0+0}{2}\right)$

$(x, y)=(2,0)$

So, equation of line is x = 2.