**Question:**

Find the equation of the line whose

(i) slope $=3$ and $y-$ intercept $=5$

(ii) slope $=-1$ and $y$ - intercept $=4$

(iii) slope $=-\frac{2}{5}$ and $y-$ intercept $=-3$

**Solution:**

(i) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept

Here, m = 3 and c = 5.

Hence, y = (3)x + (5)

i.e. y = 3x + 5

(ii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.

Here, m = - 1 and c = 4.

Hence, y = ( - 1)x + (4)

i.e. x + y = 4

(iii) Formula to be used: y = mx + c where m is the slope of the line and c is the y - intercept.

Here, $m=-\frac{2}{5}$ and $c=-3$

Hence, $y=\left(-\frac{2}{5}\right) x+(-3)$

Or, $5 y=-2 x-3$ i.e. $2 x+5 y+3=0$