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Class 9-10, JEE & NEET
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Find the equation of the straight line which passes through the point (1, – 2) and cuts off equal intercepts from axes.
The equation of line in intercept form is
Where $a$ and $b$ are the intercepts on the axis. Given that $a=b$
The above equation can be written as
On cross multiplication we get
$\Rightarrow x+y=a \ldots .1$
If equation 1 passes through the point $(1,-2)$, we get
$x=1$ and $y=-2$
Putting the value of a in equation 1 , we get
Hence, the equation of straight line is $x+y+1=0$ which passes through the point $(1,-2)$.