Find the following product:


Find the following product:
0.1y(0.1x5 + 0.1y)


To find the product, we will use distributive law as follows:

$0.1 y\left(0.1 x^{5}+0.1 y\right)$

$=(0.1 y)\left(0.1 x^{5}\right)+(0.1 y)(0.1 y)$

$=(0.1 \times 0.1)\left(y \times x^{5}\right)+(0.1 \times 0.1)(y \times y)$

$=(0.1 \times 0.1)\left(x^{5} \times y\right)+(0.1 \times 0.1)\left(y^{1+1}\right)$

$=0.01 x^{5} y+0.01 y^{2}$

Thus, the answer is $0.01 x^{5} y+0.01 y^{2}$.



Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now