Find the following product:

To find the product, we will use distributive law as follows:

$-11 a(3 a+2 b)$

$=(-11 a) \times 3 a+(-11 a) \times 2 b$

$=(-11 \times 3) \times(a \times a)+(-11 \times 2) \times(a \times b)$

$=(-33) \times\left(a^{1+1}\right)+(-22) \times(a \times b)$

$=-33 a^{2}-22 a b$

Thus, the answer is $-33 a^{2}-22 a b$.