Find the following product:

Question:

Find the following product:
−11a(3a + 2b)

Solution:

To find the product, we will use distributive law as follows:

$-11 a(3 a+2 b)$

$=(-11 a) \times 3 a+(-11 a) \times 2 b$

$=(-11 \times 3) \times(a \times a)+(-11 \times 2) \times(a \times b)$

$=(-33) \times\left(a^{1+1}\right)+(-22) \times(a \times b)$

$=-33 a^{2}-22 a b$

Thus, the answer is $-33 a^{2}-22 a b$.

 

 

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