Question:
Find the greatest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively
Solution:
Find the greatest number which divides 2011 and 2623 leaving remainder 9 and 5 respectively.
The required number when divides 2011 and 2623 leaves remainders 9 and 5 this means $2011-9=2002$ and $2623-5=2618$ are completely divisible by the number.
Therefore, the required number = H.C.F. of 2002 and 2618
By applying Euclid’s division lemma
$2618=2002 \times 1+616$
$2002=616 \times 3+154$
$610=154 \times 4+0$
H.C.F. of 2002 and 2618 = 154
Hence, the required number is 154
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