Question:
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Solution:
Given:
Sum of the parallel sides of a trapezium $=60 \mathrm{~cm}$
Area of the trapezium $=600 \mathrm{~cm}^{2}$
Area of trapezium $=\frac{1}{2} \times($ Sum of the parallel sides $) \times($ Height $)$
On putting the values :
$600=\frac{1}{2} \times 60 \times($ Height $)$
$600=30 \times($ Height $)$
Height $=\frac{600}{30}=20 \mathrm{~cm}$
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