Find the LCM and HCF of the following pairs of integers and verify that
Find the LCM and HCF of the following pairs of integers and verify that LCM Ă— HCF = Product of the integers:
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54
TO FIND: LCM and HCF of following pairs of integersÂ
TO VERIFY: L.C.M $\times$ H.C.F $=$ product of the numbers
(i) 26 and 91
Let us first find the factors of 26 and 91
$26=2 \times 13$
$91=7 \times 13$
L.C.M of 26 , and $91=2 \times 7 \times 13$
L.C.M of 26, and $91=182$
H.C.F of 26, and $91=13$
We know that,
L. C. $M \times H .$ C. $F=$ First number $\times$ Second number
$\Rightarrow 182 \times 13=26 \times 91$
$\Rightarrow 2366=2366$
Hence verified
(ii) 510 and 92
Let us first find the factors of 510 and 92
$510=2 \times 3 \times 5 \times 17$
$92=2^{2} \times 23$
L.C.M of 510 and $92=2^{2} \times 3 \times 5 \times 23 \times 17$
L.C.M of 510 and $92=23460$
H.C.F of 510 and $92=2$
We know that,
L.C.M $\times$ H.C.F $=$ First Number $\times$ Second Number
$23460 \times 2=510 \times 92$
$46920=46920$
Hence verified
(iii) 336 and 54
Let us first find the factors of 336 and 54
$336=2^{4} \times 3 \times 7$
$54=2 \times 3^{3}$
L.C.M of 336 and $54=2^{4} \times 3^{3} \times 7$
L.C.M of 336 and $54=3024$
H.C.F of 336 and $54=6$
We know that,
L.C.M $\times$ H.C.F $=$ First Number $\times$ Second Nuber
$3024 \times 6=336 \times 54$
$18144=18144$
Hence verified