Question:
Find the maximum and minimum of
$f(x)=\left(\sin x+\frac{1}{2} \cos x\right)$ in $0 \leq x \leq \frac{\pi}{2}$
Solution:
max. value is $\frac{3}{4}$ at $x=\frac{\pi}{6}$ and min. value is $\frac{1}{2}$ at $x=\frac{\pi}{2}$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.