Find the median of the following observations:

Given the numbers are  46, 64, 87, 41, 58, 77, 35, 90, 55, 92, 33

Arranging the numbers in ascending order

33, 35, 41, 46, 55, 58, 64, 77, 87, 90, 92

n = 11 (odd)

$\therefore$ Median $=\left(\frac{\mathrm{n}+1}{2}\right)^{\text {th }}$ value

$=\left(\frac{11+1}{2}\right)^{\mathrm{th}}$ value

$=6^{\text {th }}$ value $=58$

If 92 is replaced by 99 and 41 by 43

Then the new values are: 33, 35, 43, 46, 55, 58, 64, 77, 87, 90, 99

n = 11 (odd)

$\therefore$ New Median $=\left(\frac{\mathrm{n}+1}{2}\right)^{\text {th }}$ value

$=\left(\frac{11+1}{2}\right)^{\text {th }}$ value

$=6^{\text {th }}$ value $=58$