Find the missing value of p for the following distribution whose mean is 12.58
Given:
Mean $=12.58$
First of all prepare the frequency table in such a way that its first column consist of the values of the variate $\left(x_{i}\right)$ and the second column the corresponding frequencies $\left(f_{i}\right)$.
Thereafter multiply the frequency of each row with corresponding values of variable to obtain third column containing $\left(f_{i} x_{i}\right)$.
Then, sum of all entries in the column second and denoted by $\sum f_{i}$ and in the third column to obtain $\sum f_{i} x_{i}$.
We know that mean, $\bar{X}=\frac{\sum f_{i} x_{i}}{\sum f_{i}}$
$12.58=\frac{524+7 p}{50}$
By using cross multiplication method
$524+7 p=12.58 \times 50$
$7 p=629-524$
$=\frac{105}{7}$
$=15$
Hence, $p=15$
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