**Question:**

Find the multiplicative inverse (i.e., reciprocal) of:

(i) $\frac{13}{25}$

(ii) $\frac{-17}{12}$

(iii) $\frac{-7}{24}$

(iv) 18

(v) $-16$

(vi) $\frac{-3}{-5}$

(vii) $-1$

(viii) $\frac{0}{2}$

(ix) $\frac{2}{-5}$

(x) $\frac{-1}{8}$

**Solution:**

(i)Reciprocal of $\frac{13}{25}$ is $\frac{25}{13}$.

(ii) Reciprocal of $\frac{-17}{12}$ is $\frac{12}{-17}$, that is, $\frac{-12}{17}$.

(iii) Reciprocal of $\frac{-7}{24}$ is $\frac{24}{-7}$, that is, $\frac{-24}{7}$.

(iv) Reciprocal of 18 is $\frac{1}{18}$.

(v) Reciprocal of $-16$ is $\frac{1}{-16}$, that is, $\frac{-1}{16}$.

(vi) Reciprocal of $\frac{-3}{-5}$ is $\frac{-5}{-3}$, that is, $\frac{5}{3}$.

(vii) Reciprocal of $-1$ is $-1$

(viii) Reciprocal of $\frac{0}{2}$ does not exist as $\frac{2}{0}=\infty .$

(ix) Reciprocal of $\frac{2}{-5}$ is $\frac{-5}{2}$.

(x) Reciprocal of $\frac{-1}{8}$ is $-8$.