Find the product:


Find the product:
(3x2 + 5x − 9) × (3x − 5)


By horizontal method:

$\left(3 x^{2}+5 x-9\right) \times(3 x-5)$

$=3 x\left(3 x^{2}+5 x-9\right)-5\left(3 x^{2}+5 x-9\right)$

$=9 x^{3}+15 x^{2}-27 x-15 x^{2}-25 x+45$

$=9 x^{3}-52 x+45$


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