Find the product −


Find the product −3y(xy + y2) and find its value for x = 4 and y = 5.


To find the product, we will use distributive law as follows:​

$-3 y\left(x y+y^{2}\right)$

$=-3 y \times x y+(-3 y) \times y^{2}$

$=-3 x y^{1+1}-3 y^{1+2}$

$=-3 x y^{2}-3 y^{3}$

Substituting x = 4 and y = 5 in the result, we get:

$-3 x y^{2}-3 y^{3}$





Thus, the product is $\left(-3 x y^{2}-3 y^{3}\right)$, and its value for $x=4$ and $y=5$ is $(-675)$.



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