Find the remainder when $x^{3}-a x^{2}+6 x-a$ is divided by x − a.

Solution:

By long division,



Therefore, when $x^{3}-a x^{2}+6 x-a$ is divided by $x-a$, the remainder obtained is $5 a$.

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now