Find the remainder when $x^{3}-a x^{2}+6 x-a$ is divided by x − a.
Solution:
By long division,
Therefore, when $x^{3}-a x^{2}+6 x-a$ is divided by $x-a$, the remainder obtained is $5 a$.
By long division,
Therefore, when $x^{3}-a x^{2}+6 x-a$ is divided by $x-a$, the remainder obtained is $5 a$.