Find the smallest number by which 28812 must be

Question:

Find the smallest number by which 28812 must be divided so that the quotient becomes a perfect square.

Solution:

Prime factorisation of 28812:

28812 = 2 x 2 x 3 x 7 x 7 x 7 x 7


Grouping them into pairs of equal factors:

28812 = (2 x 2) x (7 x 7) x (7 x 7) x 3

The factor, 3 is not paired. Hence, the smallest number by which 28812 must be divided such that the resulting number is a perfect square is 3.

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