`

**Question:**

Find the solution of the linear equation x+2y = 8 which represents a point on

(i) X-axis

(ii) Y-axis

**Solution:**

We have, x + 2y = 8 ,..(i)

(i) When the point is on the X-axis, then put y = 0 in Eq. (i), we get

x+2 (0)=8

=> x = 8 Hence, the required point is (8, 0).

(ii) When the point is on the Y-axis, then put x = 0 in Eq. (i), we get

0 + 2y = 8

=> y = 8/2 = 4

Hence, the required point is (0, 4).