Find the sum of all numbers between 200 and 400 which are divisible by 7.

Solution:

The numbers lying between 200 and 400, which are divisible by 7, are

203, 210, 217, ­­­­­­­­… 399

∴First term, a = 203

Last term, l = 399

Common difference, d = 7

Let the number of terms of the A.P. be n.

$\therefore a_{n}=399=a+(n-1) d$

$\Rightarrow 399=203+(n-1) 7$

$\Rightarrow 7(n-1)=196$

$\Rightarrow n-1=28$

$\Rightarrow n=29$

$\therefore \mathrm{S}_{29}=\frac{29}{2}(203+399)$

$=\frac{29}{2}(602)$

$=(29)(301)$

$=8729$

Thus, the required sum is 8729.