Find the value


Find the value

$5 \sqrt{5} x^{2}+20 x+3 \sqrt{5}$


Splitting the middle term,

$=5 \sqrt{5} x^{2}+15 x+5 x+3 \sqrt{5}$

$[\therefore 20=15+5$ and $15 \times 5=5 \sqrt{5} \times 3 \sqrt{5}]$

$=5 x(\sqrt{5} x+3)+\sqrt{5}(\sqrt{5} x+3)$

$=(\sqrt{5} x+3)(5 x+\sqrt{5})$


$\therefore 5 \sqrt{5} x^{2}+20 x+3 \sqrt{5}=(\sqrt{5} x+3)(5 x+\sqrt{5})$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now