Find the value
Question:

Find the value

$x^{3}-2 x^{2} b+3 x y^{2}-6 y^{3}$

 

Solution:

Taking $x^{2}$ common in $\left(x^{3}-2 x^{2} y\right)$ and $+3 y^{2}$ common in $\left(3 x y^{2}-6 y^{3}\right)$

$=x^{2}(x-2 y)+3 y^{2}(x-2 y)$

Taking (x – 2y) common in the terms

$=(x-2 y)\left(x^{2}+3 y^{2}\right)$

$\therefore x^{3}-2 x^{2} y+3 x y^{2}-6 y^{3}=(x-2 y)\left(x^{2}+3 y^{2}\right)$

Administrator

Leave a comment

Please enter comment.
Please enter your name.