Find the value


Find the value

$x^{3}+8 y^{3}+6 x^{2} y+12 x y^{2}$


$=(x)^{3}+(2 y)^{3}+3 \times x^{2} \times 2 y+3 \times x \times(2 y)^{2}$

$=(x+2 y)^{3}$

$\left[\therefore x^{3}+y^{3}+3 x^{2} y+3 x y^{2}=(x+y)^{3}\right]$

$=(x+2 y)(x+2 y)(x+2 y)$

$\therefore x^{3}+8 y^{3}+6 x^{2} y+12 x y^{2}=(x+2 y)(x+2 y)(x+2 y)$

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