Find the value of a, so that the point (3, a) lies on the line


Find the value of a, so that the point (3, a) lies on the line 2x − 3y = 5.


The point $(3, a)$ lies on the line $2 x-3 y=5$.

If point $(3, a)$ lies on the line $2 x-3 y=5$, then

$2 x-3 y=5$

$\Rightarrow(2 \times 3)-(3 \times a)=5$

$\Rightarrow 6-3 a=5$

$\Rightarrow 3 a=1$

$\Rightarrow a=\frac{1}{3}$

Hence, the value of $a$ is $\frac{1}{3}$.

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