Question:
Find the value of the trigonometric function $\sin \left(-\frac{11 \pi}{3}\right)$
Solution:
It is known that the values of $\sin x$ repeat after an interval of $2 \pi$ or $360^{\circ}$.
$\therefore \sin \left(-\frac{11 \pi}{3}\right)=\sin \left(-\frac{11 \pi}{3}+2 \times 2 \pi\right)=\sin \left(\frac{\pi}{3}\right)=\frac{\sqrt{3}}{2}$
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