# Find the value of the trigonometric function sin(-11π/3)

Question:

Find the value of the trigonometric function $\sin \left(-\frac{11 \pi}{3}\right)$

Solution:

It is known that the values of $\sin x$ repeat after an interval of $2 \pi$ or $360^{\circ}$.

$\therefore \sin \left(-\frac{11 \pi}{3}\right)=\sin \left(-\frac{11 \pi}{3}+2 \times 2 \pi\right)=\sin \left(\frac{\pi}{3}\right)=\frac{\sqrt{3}}{2}$