Find the value of x,


Find the value of $x$, if $\left[\begin{array}{rr}3 x+y & -y \\ 2 y-x & 3\end{array}\right]=\left[\begin{array}{rr}1 & 2 \\ -5 & 3\end{array}\right]$


The corresponding elements of two equal matrices are equal.

$3 x+y=1 \quad \ldots(1)$



$\Rightarrow y=-2$

Putting the value of $y$ in eq. (1)

$3 x+(-2)=1$

$\Rightarrow 3 x-2=1$

$\Rightarrow 3 x=1+2$

$\Rightarrow 3 x=3$

$\Rightarrow x=\frac{3}{3}=1$


$\therefore x=1$

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