Find the value of x for which the numbers (5x + 2),


Find the value of for which the numbers (5x + 2), (4x − 1) and (x + 2) are in AP.


It is given that (5x + 2), (4x − 1) and (x + 2) are in AP.

$\therefore(4 x-1)-(5 x+2)=(x+2)-(4 x-1)$

$\Rightarrow 4 x-1-5 x-2=x+2-4 x+1$

$\Rightarrow-x-3=-3 x+3$

$\Rightarrow 3 x-x=3+3$

$\Rightarrow 2 x=6$

$\Rightarrow x=3$

Hence, the value of x is 3.

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