Five cards − the ten, jack, queen, king and ace of diamonds are well shuffled with their faces downwards.

Total number of cards = 5.

(a) Number of queens = 1.

$\therefore \mathrm{P}($ getting a queen $)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$

$=\frac{1}{5}$

Thus, the probability that the drawn card is the queen is $\frac{1}{5}$.

(b) When the queen is put aside, number of remaining cards = 4.

(i) Number of aces = 1.

$\therefore \mathrm{P}($ getting an ace $)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$

$=\frac{1}{4}$

Thus, the probability that the drawn card is an ace is $\frac{1}{4}$.

(ii) Number of queens = 0.

$\therefore P($ getting a queen now $)=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$

$=\frac{0}{4}=0$

Thus, the probability that the drawn card is a queen is 0.