Five coins were simultaneously tossed 1000 times,

Let the assume mean be $A=2$.

We know that mean $\bar{X}=A+\frac{1}{N} \sum_{i=1}^{n} f_{i} d_{i}$

Now, we have $N=\sum f_{i}=1000, \sum f_{i} d_{i}=470$ and $A=2$

Putting the values above in formula, we have

$\bar{X}=A+\frac{1}{N} \sum_{i=1}^{n} f_{i} d_{i}$

$=2+\frac{1}{1000} \times 470$

$=2+0.47$

$=2.47$

Hence, the mean number of heads per toss is 2.47.