**Question:**

For a CE-transistor amplifier, the audio signal voltage across the collected resistance of 2 kΩ is 2 V. Suppose the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 kΩ.

**Solution:**

Collector resistance, *R*C = 2 kΩ = 2000 Ω

Audio signal voltage across the collector resistance, *V* = 2 V

Current amplification factor of the transistor, *β* = 100

Base resistance, *R*B = 1 kΩ = 1000 Ω

Input signal voltage = *V*i

Base current = *I*B

We have the amplification relation as:

Voltage amplification $=\frac{V}{V_{i}}=\beta \frac{R_{\mathrm{C}}}{R_{\mathrm{B}}}$

$V_{i}=\frac{V R_{\mathrm{B}}}{\beta R_{\mathrm{C}}}$

$=\frac{2 \times 1000}{100 \times 2000}=0.01 \mathrm{~V}$

Therefore, the input signal voltage of the amplifier is 0.01 V.

Base resistance is given by the relation:

$R_{\mathrm{B}}=\frac{V_{\mathrm{i}}}{I_{\mathrm{B}}}$

$=\frac{0.01}{1000}=10 \times 10 \not \rho \mathrm{A}$

Therefore, the base current of the amplifier is 10 μA.

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.