For a glass prism (µ = √3 ) the angle of minimum

Question:

For a glass prism (µ = √3 ) the angle of minimum deviation is equal to the angle of the prism. Find the angle of the prism.

Solution:

μ = sin[(A + δm)/2]/sin (A/2)

Substituting the values of μ = sin A/sin A/2

μ = sin A/sin A/2 = 2 cos A/2

A = 60o

Therefore, the required angle is 60o

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