For all rational numbers $x$ and $y,(x) \times(y)=(y) \times(x)$

True.

Let $x=2, y=3$

Then,

LHS $=2 \times 3$

$=6$

$\mathrm{RHS}=3 \times 2$

By comparing $\mathrm{LHS}$ and RHS

$6=6$

$\mathrm{LHS}=\mathrm{RHS}$

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