Question:
For full scale deflection of total 50 divisions, $50 \mathrm{mV}$ voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is $2 \mathrm{div} / \mathrm{mA}$ will be :
Correct Option: , 4
Solution:
$\mathrm{I}_{\max }=\frac{50}{2}=25 \mathrm{~mA}$
$\mathbf{R}=\frac{\mathrm{V}}{\mathrm{I}}=\frac{50 \mathrm{mV}}{25 \mathrm{~mA}}=2 \Omega$
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