For the Balmer series in the spectrum of

Question:

For the Balmer series in the spectrum of $\mathrm{H}$ atom, $\bar{v}=R_{H}\left\{\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right\}$, the correct statements among (I) to (IV) are:

(I) As wavelength decreases, the lines in the series converge

(II) The integer $n_{1}$ is equal to 2

(III) The lines of longest wavelength corresponds to $n_{2}=3$

(IV) The ionization energy of hydrogen can be calculated from wave number of these lines

  1. (I), (III), (IV)

  2. (i), (II), (III)

  3. (I), (II), (IV)

  4. (II), (III), (IV)


Correct Option:

Solution:

In the Balmer series of H-atom the transition takes place from the higher oribtal to $\mathrm{n}=2$. Therefore the longest wave length corresponds to $n_{1}=2$ and $n_{2}=3$. As the wave length decreases, the lines in the series converges. Hence, statement I, II, III are the correct statements among the given options.

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