For the Balmer series in the spectrum of $\mathrm{H}$ atom, $\bar{v}=R_{H}\left\{\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}}\right\}$, the correct statements among (I) to (IV) are:
(I) As wavelength decreases, the lines in the series converge
(II) The integer $n_{1}$ is equal to 2
(III) The lines of longest wavelength corresponds to $n_{2}=3$
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
Correct Option:
In the Balmer series of H-atom the transition takes place from the higher oribtal to $\mathrm{n}=2$. Therefore the longest wave length corresponds to $n_{1}=2$ and $n_{2}=3$. As the wave length decreases, the lines in the series converges. Hence, statement I, II, III are the correct statements among the given options.
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