Question:
For the following distribution,
the sum of lower limits of the median class and modal class is
(a) 15
(b) 25
(c) 30
(d) 35
Solution:
Now, $\frac{N}{2}=\frac{66}{2}=33$, which lies in the interval $10-15$. Therefore, lower limit of the median class is
10. . ,
The highest frequency is 20, which lies in the interval 15-20. Therefore, lower limit of modal class is 15. Hence, required sum is 10 + 15 = 25.
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