For the following distribution,


For the following distribution,

the sum of lower limits of the median class and modal class is

(a) 15                               

(b) 25                                   

(c) 30                        

(d) 35


Now, $\frac{N}{2}=\frac{66}{2}=33$, which lies in the interval $10-15$. Therefore, lower limit of the median class is

10.                                              .         ,
The highest frequency is 20, which lies in the interval 15-20. Therefore, lower limit of modal class is 15. Hence, required sum is 10 + 15 = 25.

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