Question.
Give the number of electrons in the species $\mathrm{H}_{2}^{+}, \mathrm{H}_{2}$ and $\mathrm{O}_{2}^{+}$
Give the number of electrons in the species $\mathrm{H}_{2}^{+}, \mathrm{H}_{2}$ and $\mathrm{O}_{2}^{+}$
Solution:
$\mathrm{H}_{2}^{+}$:
Number of electrons present in hydrogen molecule (H2) = 1 + 1 = 2
$\therefore$ Number of electrons in $\mathrm{H}_{2}^{+}=2-1=1$
H2:
Number of electrons in H2 = 1 + 1 = 2
$\mathrm{O}_{2}^{+}$
Number of electrons present in oxygen molecule $\left(\mathrm{O}_{2}\right)=8+8=16$
$\therefore$ Number of electrons in $\mathrm{O}_{2}^{+}=16-1=15$
$\mathrm{H}_{2}^{+}$:
Number of electrons present in hydrogen molecule (H2) = 1 + 1 = 2
$\therefore$ Number of electrons in $\mathrm{H}_{2}^{+}=2-1=1$
H2:
Number of electrons in H2 = 1 + 1 = 2
$\mathrm{O}_{2}^{+}$
Number of electrons present in oxygen molecule $\left(\mathrm{O}_{2}\right)=8+8=16$
$\therefore$ Number of electrons in $\mathrm{O}_{2}^{+}=16-1=15$
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