Given that ΔH = 0 for mixing of two gases.

Question:

Given that ΔH = 0 for mixing of two gases. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not?

Solution:

A negative ∆G means the reaction will be the spontaneous included contribution of the other factors like enthalpy(H) and entropy(S).

∆G= ∆H – T∆S

∆H being 0,

∆G will be negative (as the positive value of ∆S will give a more negative T∆S)

∆H=0 ; ∆G= -T∆S= negative.

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