How many different products can be obtained by multiplying two or more

Question:

How many different products can be obtained by multiplying two or more of the numbers 3, 5, 7, 11 without repetition?

Solution:

The given no. is 3,5,7,11.

The no. of different products when two or more is taking= the no. of ways of taking the product of two no.+ the no. of ways of taking the product of three no. + the no. of ways of taking the product of four no.

$={ }^{4} \mathrm{C}_{2}+{ }^{4} \mathrm{C}_{3}+{ }^{4} \mathrm{C}_{4}$

Applying ${ }^{n} C_{r}=\frac{n !}{r !(n-r) !}$

$=6+4+1$

$=11$

 

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