How much copper can be obtained from 100 g of copper sulphate (CuSO4)?

Solution:

1 mole of $\mathrm{CuSO}_{4}$ contains 1 mole of copper.

Molar mass of CuSO4= (63.5) + (32.00) + 4(16.00)

= 63.5 + 32.00 + 64.00

= 159.5 g

159.5 g of CuSO4contains 63.5 g of copper

$\Rightarrow 100 \mathrm{~g}$ of $\mathrm{CuSO}_{4}$ will contain $\frac{63.5 \times 100 \mathrm{~g}}{159.5}$ of copper.

$\therefore$ Amount of copper that can be obtained from $100 \mathrm{~g} \mathrm{CuSO}_{4} \quad=\frac{63.5 \times 100}{159.5}$

= 39.81 g