Question:
I toss three coins together. The possible outcomes are no heads, 1 head, 2 head and 3 heads. So, I say that probability of no heads is $\frac{1}{4}$. What
is wrong with this conclusion?
Solution:
I toss three coins together [given]
So, total number of outcomes = 23 = 8
and possible outcomes are (HHH), (HTT), (THT), (TTH),(HHT), (THH), (HIH)and (TTT)
Now, probability of getting no head $=\frac{1}{8}$
Hence, the given conclusion is wrong because the probability of no head is $\frac{1}{8}$ not $\frac{1}{4}$.
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