Question:
If $1176=2^{a} \times 3^{b} \times 7$, Find $a$, $b$, and $c$.
Solution:
Given that 2,3 and 7 are factors of 1176 .
Taking out the LCM of 1176 , we get $2^{3} \times 3^{1} \times 7^{2}=2^{a} \times 3^{b} \times 7^{c}$
By comparing, we get
$a=3, b=1$ and $c=2$
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