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Question:

$Y=A \sin \left(\omega t+\phi_{0}\right)$ is the time - displacement equation of a SHM, At $t=0$ the displacement of the particle is $Y=\frac{A}{2}$ and it is moving along negative $x$-direction. Then the initial phase angle $\phi_{0}$ will be

  1. (1) $\frac{\pi}{6}$

  2. (2) $\frac{\pi}{3}$

  3. (3) $\frac{2 \pi}{3}$

  4. (4) $\frac{5 \pi}{6}$


Correct Option: , 4

Solution:

The initial phase angle $\phi_{0}=\pi-\frac{\pi}{6}$

$=\frac{5-\pi}{6}$

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