If A(1, 2), B(-3, 2) and C(3, 2) be the vertices of a ΔABC, show that


If $A(1,2), B(-3,2)$ and $C(3,2)$ be the vertices of a $\triangle A B C$, show that

(i) $\tan \mathrm{A}=2$

(ii) $\tan \mathrm{B}=\frac{2}{3}$

(iii) $\tan \mathrm{C}=\frac{4}{7}$



Points A,B,C lie on a same line, therefore the slope of each line is same and hence it does not form a triangle.


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