Question:
If $A(1,2), B(-3,2)$ and $C(3,2)$ be the vertices of a $\triangle A B C$, show that
(i) $\tan \mathrm{A}=2$
(ii) $\tan \mathrm{B}=\frac{2}{3}$
(iii) $\tan \mathrm{C}=\frac{4}{7}$
Solution:
Points A,B,C lie on a same line, therefore the slope of each line is same and hence it does not form a triangle.
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