If α, β are the zeros of the polynomial 2y2 + 7y + 5,

Let $\alpha$ and $\beta$ are the zeros of the polynomial $f(x)=2 y^{2}+7 y+5$. Then

The sum of the zeros $=\frac{-\text { Coefficient of } y}{\text { Coefficient of } y^{2}}=\frac{-7}{2}$ The product of the zeros $=\frac{\text { Constant term }}{\text { Co-efficient of } y^{2}}=\frac{5}{2}$

Then the value of $\alpha+\beta+\alpha \beta$ is

$\alpha+\beta+\alpha \beta$

$=\frac{-7}{2}+\frac{5}{2}$

$=\frac{-7+5}{2}$

$=\frac{-2}{2}$

$=-1$

Hence, the value of $\alpha+\beta+\alpha \beta$ is $-1$