If f(x) = cos [e] x + cos [–e] x,


If $f(x)=\cos [e] x+\cos [-e] x$, then $f(\pi)=$ ___________.


Given: f(x) = cos[e]x + cos[–e]x

$f(x)=\cos [e] x+\cos [-e] x$

$=\cos 2 x+\cos (-3 x) \quad(\because e=2.718$ approx $)$

$=\cos 2 x+\cos 3 x$

$\Rightarrow f(\pi)=\cos 2 \pi+\cos 3 \pi$



Hence, $f(\pi)=\underline{0}$



Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now