If f(x) = x3 + x2 − ax + b is divisible


If $l(x)=x^{3}+x^{2}-a x+b$ is divisible by $x^{2}-x$ write the value of $a$ and $b$.


We are given $f(x)=x^{3}+x^{2}-a x+b$ is exactly divisible by $x^{2}-x$ then the remainder should be zero

Therefore Quotient $=x+2$ and

Remainder $=x(2-a)+b$

Now, Remainder $=0$


$x(2-a)+b=0 x+0$

Equating coefficient of $\mathrm{x}$, we get



Equating constant term


Hence, the value of $a$ and $b$ are $a=2, b=0$

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