If, for a positive integer n, the quadratic equation,

Question:

If, for a positive integer n, the quadratic equation, $x(x+1)+(x+1)(x+2)+\ldots .+(x+n-1)(x+n)=10 n$ has two consecutive integral solutions, then $\mathrm{n}$ is equal to :

  1. 11

  2. 12

  3. 9

  4. 10


Correct Option: 1

Solution:


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