If p(x) = 5 − 4x + 2×2,
Question:

If $p(x)=5-4 x+2 x^{2}$, find

(i) $p(0)$,

(ii) $p(3)$,

(iii) $p(-2)$

Solution:

(i) $p(x)=5-4 x+2 x^{2}$

$\Rightarrow p(0)=\left(5-4 \times 0+2 \times 0^{2}\right)$

$=(5-0+0)$

$=5$

(ii) $p(x)=5-4 x+2 x^{2}$

$\Rightarrow p(3)=\left(5-4 \times 3+2 \times 3^{2}\right)$

$=(5-12+18)$

$=11$

(iii) $p(x)=5-4 x+2 x^{2}$

$\Rightarrow p(-2)=\left[5-4 \times(-2)+2 \times(-2)^{2}\right]$

$=(5+8+8)$

$=21$

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